3.434 \(\int \frac {(a+b \log (c (d (e+f x)^p)^q))^2}{(g+h x)^3} \, dx\)

Optimal. Leaf size=222 \[ -\frac {b f^2 p q \log \left (\frac {f g-e h}{h (e+f x)}+1\right ) \left (a+b \log \left (c \left (d (e+f x)^p\right )^q\right )\right )}{h (f g-e h)^2}-\frac {b f p q (e+f x) \left (a+b \log \left (c \left (d (e+f x)^p\right )^q\right )\right )}{(g+h x) (f g-e h)^2}-\frac {\left (a+b \log \left (c \left (d (e+f x)^p\right )^q\right )\right )^2}{2 h (g+h x)^2}+\frac {b^2 f^2 p^2 q^2 \text {Li}_2\left (-\frac {f g-e h}{h (e+f x)}\right )}{h (f g-e h)^2}+\frac {b^2 f^2 p^2 q^2 \log (g+h x)}{h (f g-e h)^2} \]

[Out]

-b*f*p*q*(f*x+e)*(a+b*ln(c*(d*(f*x+e)^p)^q))/(-e*h+f*g)^2/(h*x+g)-1/2*(a+b*ln(c*(d*(f*x+e)^p)^q))^2/h/(h*x+g)^
2+b^2*f^2*p^2*q^2*ln(h*x+g)/h/(-e*h+f*g)^2-b*f^2*p*q*(a+b*ln(c*(d*(f*x+e)^p)^q))*ln(1+(-e*h+f*g)/h/(f*x+e))/h/
(-e*h+f*g)^2+b^2*f^2*p^2*q^2*polylog(2,(e*h-f*g)/h/(f*x+e))/h/(-e*h+f*g)^2

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Rubi [A]  time = 0.82, antiderivative size = 257, normalized size of antiderivative = 1.16, number of steps used = 10, number of rules used = 10, integrand size = 28, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.357, Rules used = {2398, 2411, 2347, 2344, 2301, 2317, 2391, 2314, 31, 2445} \[ -\frac {b^2 f^2 p^2 q^2 \text {PolyLog}\left (2,-\frac {h (e+f x)}{f g-e h}\right )}{h (f g-e h)^2}+\frac {f^2 \left (a+b \log \left (c \left (d (e+f x)^p\right )^q\right )\right )^2}{2 h (f g-e h)^2}-\frac {b f^2 p q \log \left (\frac {f (g+h x)}{f g-e h}\right ) \left (a+b \log \left (c \left (d (e+f x)^p\right )^q\right )\right )}{h (f g-e h)^2}-\frac {b f p q (e+f x) \left (a+b \log \left (c \left (d (e+f x)^p\right )^q\right )\right )}{(g+h x) (f g-e h)^2}-\frac {\left (a+b \log \left (c \left (d (e+f x)^p\right )^q\right )\right )^2}{2 h (g+h x)^2}+\frac {b^2 f^2 p^2 q^2 \log (g+h x)}{h (f g-e h)^2} \]

Antiderivative was successfully verified.

[In]

Int[(a + b*Log[c*(d*(e + f*x)^p)^q])^2/(g + h*x)^3,x]

[Out]

-((b*f*p*q*(e + f*x)*(a + b*Log[c*(d*(e + f*x)^p)^q]))/((f*g - e*h)^2*(g + h*x))) + (f^2*(a + b*Log[c*(d*(e +
f*x)^p)^q])^2)/(2*h*(f*g - e*h)^2) - (a + b*Log[c*(d*(e + f*x)^p)^q])^2/(2*h*(g + h*x)^2) + (b^2*f^2*p^2*q^2*L
og[g + h*x])/(h*(f*g - e*h)^2) - (b*f^2*p*q*(a + b*Log[c*(d*(e + f*x)^p)^q])*Log[(f*(g + h*x))/(f*g - e*h)])/(
h*(f*g - e*h)^2) - (b^2*f^2*p^2*q^2*PolyLog[2, -((h*(e + f*x))/(f*g - e*h))])/(h*(f*g - e*h)^2)

Rule 31

Int[((a_) + (b_.)*(x_))^(-1), x_Symbol] :> Simp[Log[RemoveContent[a + b*x, x]]/b, x] /; FreeQ[{a, b}, x]

Rule 2301

Int[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))/(x_), x_Symbol] :> Simp[(a + b*Log[c*x^n])^2/(2*b*n), x] /; FreeQ[{a
, b, c, n}, x]

Rule 2314

Int[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))*((d_) + (e_.)*(x_)^(r_.))^(q_), x_Symbol] :> Simp[(x*(d + e*x^r)^(q
+ 1)*(a + b*Log[c*x^n]))/d, x] - Dist[(b*n)/d, Int[(d + e*x^r)^(q + 1), x], x] /; FreeQ[{a, b, c, d, e, n, q,
r}, x] && EqQ[r*(q + 1) + 1, 0]

Rule 2317

Int[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))^(p_.)/((d_) + (e_.)*(x_)), x_Symbol] :> Simp[(Log[1 + (e*x)/d]*(a +
b*Log[c*x^n])^p)/e, x] - Dist[(b*n*p)/e, Int[(Log[1 + (e*x)/d]*(a + b*Log[c*x^n])^(p - 1))/x, x], x] /; FreeQ[
{a, b, c, d, e, n}, x] && IGtQ[p, 0]

Rule 2344

Int[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))^(p_.)/((x_)*((d_) + (e_.)*(x_))), x_Symbol] :> Dist[1/d, Int[(a + b*
Log[c*x^n])^p/x, x], x] - Dist[e/d, Int[(a + b*Log[c*x^n])^p/(d + e*x), x], x] /; FreeQ[{a, b, c, d, e, n}, x]
&& IGtQ[p, 0]

Rule 2347

Int[(((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))^(p_.)*((d_) + (e_.)*(x_))^(q_))/(x_), x_Symbol] :> Dist[1/d, Int[((
d + e*x)^(q + 1)*(a + b*Log[c*x^n])^p)/x, x], x] - Dist[e/d, Int[(d + e*x)^q*(a + b*Log[c*x^n])^p, x], x] /; F
reeQ[{a, b, c, d, e, n}, x] && IGtQ[p, 0] && LtQ[q, -1] && IntegerQ[2*q]

Rule 2391

Int[Log[(c_.)*((d_) + (e_.)*(x_)^(n_.))]/(x_), x_Symbol] :> -Simp[PolyLog[2, -(c*e*x^n)]/n, x] /; FreeQ[{c, d,
e, n}, x] && EqQ[c*d, 1]

Rule 2398

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_))^(n_.)]*(b_.))^(p_)*((f_.) + (g_.)*(x_))^(q_.), x_Symbol] :> Simp[((
f + g*x)^(q + 1)*(a + b*Log[c*(d + e*x)^n])^p)/(g*(q + 1)), x] - Dist[(b*e*n*p)/(g*(q + 1)), Int[((f + g*x)^(q
+ 1)*(a + b*Log[c*(d + e*x)^n])^(p - 1))/(d + e*x), x], x] /; FreeQ[{a, b, c, d, e, f, g, n, q}, x] && NeQ[e*
f - d*g, 0] && GtQ[p, 0] && NeQ[q, -1] && IntegersQ[2*p, 2*q] && ( !IGtQ[q, 0] || (EqQ[p, 2] && NeQ[q, 1]))

Rule 2411

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_))^(n_.)]*(b_.))^(p_.)*((f_.) + (g_.)*(x_))^(q_.)*((h_.) + (i_.)*(x_))
^(r_.), x_Symbol] :> Dist[1/e, Subst[Int[((g*x)/e)^q*((e*h - d*i)/e + (i*x)/e)^r*(a + b*Log[c*x^n])^p, x], x,
d + e*x], x] /; FreeQ[{a, b, c, d, e, f, g, h, i, n, p, q, r}, x] && EqQ[e*f - d*g, 0] && (IGtQ[p, 0] || IGtQ[
r, 0]) && IntegerQ[2*r]

Rule 2445

Int[((a_.) + Log[(c_.)*((d_.)*((e_.) + (f_.)*(x_))^(m_.))^(n_)]*(b_.))^(p_.)*(u_.), x_Symbol] :> Subst[Int[u*(
a + b*Log[c*d^n*(e + f*x)^(m*n)])^p, x], c*d^n*(e + f*x)^(m*n), c*(d*(e + f*x)^m)^n] /; FreeQ[{a, b, c, d, e,
f, m, n, p}, x] &&  !IntegerQ[n] &&  !(EqQ[d, 1] && EqQ[m, 1]) && IntegralFreeQ[IntHide[u*(a + b*Log[c*d^n*(e
+ f*x)^(m*n)])^p, x]]

Rubi steps

\begin {align*} \int \frac {\left (a+b \log \left (c \left (d (e+f x)^p\right )^q\right )\right )^2}{(g+h x)^3} \, dx &=\operatorname {Subst}\left (\int \frac {\left (a+b \log \left (c d^q (e+f x)^{p q}\right )\right )^2}{(g+h x)^3} \, dx,c d^q (e+f x)^{p q},c \left (d (e+f x)^p\right )^q\right )\\ &=-\frac {\left (a+b \log \left (c \left (d (e+f x)^p\right )^q\right )\right )^2}{2 h (g+h x)^2}+\operatorname {Subst}\left (\frac {(b f p q) \int \frac {a+b \log \left (c d^q (e+f x)^{p q}\right )}{(e+f x) (g+h x)^2} \, dx}{h},c d^q (e+f x)^{p q},c \left (d (e+f x)^p\right )^q\right )\\ &=-\frac {\left (a+b \log \left (c \left (d (e+f x)^p\right )^q\right )\right )^2}{2 h (g+h x)^2}+\operatorname {Subst}\left (\frac {(b p q) \operatorname {Subst}\left (\int \frac {a+b \log \left (c d^q x^{p q}\right )}{x \left (\frac {f g-e h}{f}+\frac {h x}{f}\right )^2} \, dx,x,e+f x\right )}{h},c d^q (e+f x)^{p q},c \left (d (e+f x)^p\right )^q\right )\\ &=-\frac {\left (a+b \log \left (c \left (d (e+f x)^p\right )^q\right )\right )^2}{2 h (g+h x)^2}-\operatorname {Subst}\left (\frac {(b p q) \operatorname {Subst}\left (\int \frac {a+b \log \left (c d^q x^{p q}\right )}{\left (\frac {f g-e h}{f}+\frac {h x}{f}\right )^2} \, dx,x,e+f x\right )}{f g-e h},c d^q (e+f x)^{p q},c \left (d (e+f x)^p\right )^q\right )+\operatorname {Subst}\left (\frac {(b f p q) \operatorname {Subst}\left (\int \frac {a+b \log \left (c d^q x^{p q}\right )}{x \left (\frac {f g-e h}{f}+\frac {h x}{f}\right )} \, dx,x,e+f x\right )}{h (f g-e h)},c d^q (e+f x)^{p q},c \left (d (e+f x)^p\right )^q\right )\\ &=-\frac {b f p q (e+f x) \left (a+b \log \left (c \left (d (e+f x)^p\right )^q\right )\right )}{(f g-e h)^2 (g+h x)}-\frac {\left (a+b \log \left (c \left (d (e+f x)^p\right )^q\right )\right )^2}{2 h (g+h x)^2}-\operatorname {Subst}\left (\frac {(b f p q) \operatorname {Subst}\left (\int \frac {a+b \log \left (c d^q x^{p q}\right )}{\frac {f g-e h}{f}+\frac {h x}{f}} \, dx,x,e+f x\right )}{(f g-e h)^2},c d^q (e+f x)^{p q},c \left (d (e+f x)^p\right )^q\right )+\operatorname {Subst}\left (\frac {\left (b f^2 p q\right ) \operatorname {Subst}\left (\int \frac {a+b \log \left (c d^q x^{p q}\right )}{x} \, dx,x,e+f x\right )}{h (f g-e h)^2},c d^q (e+f x)^{p q},c \left (d (e+f x)^p\right )^q\right )+\operatorname {Subst}\left (\frac {\left (b^2 f p^2 q^2\right ) \operatorname {Subst}\left (\int \frac {1}{\frac {f g-e h}{f}+\frac {h x}{f}} \, dx,x,e+f x\right )}{(f g-e h)^2},c d^q (e+f x)^{p q},c \left (d (e+f x)^p\right )^q\right )\\ &=-\frac {b f p q (e+f x) \left (a+b \log \left (c \left (d (e+f x)^p\right )^q\right )\right )}{(f g-e h)^2 (g+h x)}+\frac {f^2 \left (a+b \log \left (c \left (d (e+f x)^p\right )^q\right )\right )^2}{2 h (f g-e h)^2}-\frac {\left (a+b \log \left (c \left (d (e+f x)^p\right )^q\right )\right )^2}{2 h (g+h x)^2}+\frac {b^2 f^2 p^2 q^2 \log (g+h x)}{h (f g-e h)^2}-\frac {b f^2 p q \left (a+b \log \left (c \left (d (e+f x)^p\right )^q\right )\right ) \log \left (\frac {f (g+h x)}{f g-e h}\right )}{h (f g-e h)^2}+\operatorname {Subst}\left (\frac {\left (b^2 f^2 p^2 q^2\right ) \operatorname {Subst}\left (\int \frac {\log \left (1+\frac {h x}{f g-e h}\right )}{x} \, dx,x,e+f x\right )}{h (f g-e h)^2},c d^q (e+f x)^{p q},c \left (d (e+f x)^p\right )^q\right )\\ &=-\frac {b f p q (e+f x) \left (a+b \log \left (c \left (d (e+f x)^p\right )^q\right )\right )}{(f g-e h)^2 (g+h x)}+\frac {f^2 \left (a+b \log \left (c \left (d (e+f x)^p\right )^q\right )\right )^2}{2 h (f g-e h)^2}-\frac {\left (a+b \log \left (c \left (d (e+f x)^p\right )^q\right )\right )^2}{2 h (g+h x)^2}+\frac {b^2 f^2 p^2 q^2 \log (g+h x)}{h (f g-e h)^2}-\frac {b f^2 p q \left (a+b \log \left (c \left (d (e+f x)^p\right )^q\right )\right ) \log \left (\frac {f (g+h x)}{f g-e h}\right )}{h (f g-e h)^2}-\frac {b^2 f^2 p^2 q^2 \text {Li}_2\left (-\frac {h (e+f x)}{f g-e h}\right )}{h (f g-e h)^2}\\ \end {align*}

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Mathematica [A]  time = 0.47, size = 316, normalized size = 1.42 \[ -\frac {\frac {2 b p q \left (h (e+f x) \log (e+f x) (e h-f (2 g+h x))+f (g+h x) \left (f (g+h x) \log \left (\frac {f (g+h x)}{f g-e h}\right )+h (e+f x)\right )\right ) \left (a+b \log \left (c \left (d (e+f x)^p\right )^q\right )-b p q \log (e+f x)\right )}{(f g-e h)^2}+\left (a+b \log \left (c \left (d (e+f x)^p\right )^q\right )-b p q \log (e+f x)\right )^2+\frac {b^2 p^2 q^2 \left (2 f^2 (g+h x)^2 \text {Li}_2\left (\frac {h (e+f x)}{e h-f g}\right )-2 f^2 (g+h x)^2 \log \left (\frac {f (g+h x)}{f g-e h}\right )+h (e+f x) \log ^2(e+f x) (e h-f (2 g+h x))+2 f (g+h x) \log (e+f x) \left (f (g+h x) \log \left (\frac {f (g+h x)}{f g-e h}\right )+h (e+f x)\right )\right )}{(f g-e h)^2}}{2 h (g+h x)^2} \]

Antiderivative was successfully verified.

[In]

Integrate[(a + b*Log[c*(d*(e + f*x)^p)^q])^2/(g + h*x)^3,x]

[Out]

-1/2*((a - b*p*q*Log[e + f*x] + b*Log[c*(d*(e + f*x)^p)^q])^2 + (2*b*p*q*(a - b*p*q*Log[e + f*x] + b*Log[c*(d*
(e + f*x)^p)^q])*(h*(e + f*x)*(e*h - f*(2*g + h*x))*Log[e + f*x] + f*(g + h*x)*(h*(e + f*x) + f*(g + h*x)*Log[
(f*(g + h*x))/(f*g - e*h)])))/(f*g - e*h)^2 + (b^2*p^2*q^2*(h*(e + f*x)*(e*h - f*(2*g + h*x))*Log[e + f*x]^2 -
2*f^2*(g + h*x)^2*Log[(f*(g + h*x))/(f*g - e*h)] + 2*f*(g + h*x)*Log[e + f*x]*(h*(e + f*x) + f*(g + h*x)*Log[
(f*(g + h*x))/(f*g - e*h)]) + 2*f^2*(g + h*x)^2*PolyLog[2, (h*(e + f*x))/(-(f*g) + e*h)]))/(f*g - e*h)^2)/(h*(
g + h*x)^2)

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fricas [F]  time = 0.68, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {b^{2} \log \left (\left ({\left (f x + e\right )}^{p} d\right )^{q} c\right )^{2} + 2 \, a b \log \left (\left ({\left (f x + e\right )}^{p} d\right )^{q} c\right ) + a^{2}}{h^{3} x^{3} + 3 \, g h^{2} x^{2} + 3 \, g^{2} h x + g^{3}}, x\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a+b*log(c*(d*(f*x+e)^p)^q))^2/(h*x+g)^3,x, algorithm="fricas")

[Out]

integral((b^2*log(((f*x + e)^p*d)^q*c)^2 + 2*a*b*log(((f*x + e)^p*d)^q*c) + a^2)/(h^3*x^3 + 3*g*h^2*x^2 + 3*g^
2*h*x + g^3), x)

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\left (b \log \left (\left ({\left (f x + e\right )}^{p} d\right )^{q} c\right ) + a\right )}^{2}}{{\left (h x + g\right )}^{3}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a+b*log(c*(d*(f*x+e)^p)^q))^2/(h*x+g)^3,x, algorithm="giac")

[Out]

integrate((b*log(((f*x + e)^p*d)^q*c) + a)^2/(h*x + g)^3, x)

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maple [F]  time = 0.35, size = 0, normalized size = 0.00 \[ \int \frac {\left (b \ln \left (c \left (d \left (f x +e \right )^{p}\right )^{q}\right )+a \right )^{2}}{\left (h x +g \right )^{3}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((b*ln(c*(d*(f*x+e)^p)^q)+a)^2/(h*x+g)^3,x)

[Out]

int((b*ln(c*(d*(f*x+e)^p)^q)+a)^2/(h*x+g)^3,x)

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ a b f p q {\left (\frac {f \log \left (f x + e\right )}{f^{2} g^{2} h - 2 \, e f g h^{2} + e^{2} h^{3}} - \frac {f \log \left (h x + g\right )}{f^{2} g^{2} h - 2 \, e f g h^{2} + e^{2} h^{3}} + \frac {1}{f g^{2} h - e g h^{2} + {\left (f g h^{2} - e h^{3}\right )} x}\right )} - \frac {1}{2} \, b^{2} {\left (\frac {\log \left ({\left ({\left (f x + e\right )}^{p}\right )}^{q}\right )^{2}}{h^{3} x^{2} + 2 \, g h^{2} x + g^{2} h} - 2 \, \int \frac {e h q^{2} \log \relax (d)^{2} + 2 \, e h q \log \relax (c) \log \relax (d) + e h \log \relax (c)^{2} + {\left (f h q^{2} \log \relax (d)^{2} + 2 \, f h q \log \relax (c) \log \relax (d) + f h \log \relax (c)^{2}\right )} x + {\left (f g p q + 2 \, e h q \log \relax (d) + 2 \, e h \log \relax (c) + {\left (f h p q + 2 \, f h q \log \relax (d) + 2 \, f h \log \relax (c)\right )} x\right )} \log \left ({\left ({\left (f x + e\right )}^{p}\right )}^{q}\right )}{f h^{4} x^{4} + e g^{3} h + {\left (3 \, f g h^{3} + e h^{4}\right )} x^{3} + 3 \, {\left (f g^{2} h^{2} + e g h^{3}\right )} x^{2} + {\left (f g^{3} h + 3 \, e g^{2} h^{2}\right )} x}\,{d x}\right )} - \frac {a b \log \left (\left ({\left (f x + e\right )}^{p} d\right )^{q} c\right )}{h^{3} x^{2} + 2 \, g h^{2} x + g^{2} h} - \frac {a^{2}}{2 \, {\left (h^{3} x^{2} + 2 \, g h^{2} x + g^{2} h\right )}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a+b*log(c*(d*(f*x+e)^p)^q))^2/(h*x+g)^3,x, algorithm="maxima")

[Out]

a*b*f*p*q*(f*log(f*x + e)/(f^2*g^2*h - 2*e*f*g*h^2 + e^2*h^3) - f*log(h*x + g)/(f^2*g^2*h - 2*e*f*g*h^2 + e^2*
h^3) + 1/(f*g^2*h - e*g*h^2 + (f*g*h^2 - e*h^3)*x)) - 1/2*b^2*(log(((f*x + e)^p)^q)^2/(h^3*x^2 + 2*g*h^2*x + g
^2*h) - 2*integrate((e*h*q^2*log(d)^2 + 2*e*h*q*log(c)*log(d) + e*h*log(c)^2 + (f*h*q^2*log(d)^2 + 2*f*h*q*log
(c)*log(d) + f*h*log(c)^2)*x + (f*g*p*q + 2*e*h*q*log(d) + 2*e*h*log(c) + (f*h*p*q + 2*f*h*q*log(d) + 2*f*h*lo
g(c))*x)*log(((f*x + e)^p)^q))/(f*h^4*x^4 + e*g^3*h + (3*f*g*h^3 + e*h^4)*x^3 + 3*(f*g^2*h^2 + e*g*h^3)*x^2 +
(f*g^3*h + 3*e*g^2*h^2)*x), x)) - a*b*log(((f*x + e)^p*d)^q*c)/(h^3*x^2 + 2*g*h^2*x + g^2*h) - 1/2*a^2/(h^3*x^
2 + 2*g*h^2*x + g^2*h)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.00 \[ \int \frac {{\left (a+b\,\ln \left (c\,{\left (d\,{\left (e+f\,x\right )}^p\right )}^q\right )\right )}^2}{{\left (g+h\,x\right )}^3} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a + b*log(c*(d*(e + f*x)^p)^q))^2/(g + h*x)^3,x)

[Out]

int((a + b*log(c*(d*(e + f*x)^p)^q))^2/(g + h*x)^3, x)

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\left (a + b \log {\left (c \left (d \left (e + f x\right )^{p}\right )^{q} \right )}\right )^{2}}{\left (g + h x\right )^{3}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a+b*ln(c*(d*(f*x+e)**p)**q))**2/(h*x+g)**3,x)

[Out]

Integral((a + b*log(c*(d*(e + f*x)**p)**q))**2/(g + h*x)**3, x)

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